2sin^2-3cos+1=0

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Solution for 2sin^2-3cos+1=0 equation:


Simplifying
2sin2 + -3cos + 1 = 0

Reorder the terms:
1 + -3cos + 2in2s = 0

Solving
1 + -3cos + 2in2s = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -3cos + -1 + 2in2s = 0 + -1

Reorder the terms:
1 + -1 + -3cos + 2in2s = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3cos + 2in2s = 0 + -1
-3cos + 2in2s = 0 + -1

Combine like terms: 0 + -1 = -1
-3cos + 2in2s = -1

Add '-2in2s' to each side of the equation.
-3cos + 2in2s + -2in2s = -1 + -2in2s

Combine like terms: 2in2s + -2in2s = 0
-3cos + 0 = -1 + -2in2s
-3cos = -1 + -2in2s

Divide each side by '-3os'.
c = 0.3333333333o-1s-1 + 0.6666666667in2o-1

Simplifying
c = 0.3333333333o-1s-1 + 0.6666666667in2o-1

Reorder the terms:
c = 0.6666666667in2o-1 + 0.3333333333o-1s-1

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